An efficient asymmetric removal lemma and its limitations

The triangle removal states that if G contains $\varepsilon n^2$ edge-disjoint triangles, then G contains $\delta (\varepsilon )n^3$ triangles. Unfortunately, there are no sensible bounds on the order of growth of $\delta (\varepsilon )$ , and at any rate, it is known that $\...

Full description

Saved in:
Bibliographic Details
Main Authors: Lior Gishboliner, Asaf Shapira, Yuval Wigderson
Format: Article
Language:English
Published: Cambridge University Press 2025-01-01
Series:Forum of Mathematics, Sigma
Subjects:
Online Access:https://www.cambridge.org/core/product/identifier/S2050509424000689/type/journal_article
Tags: Add Tag
No Tags, Be the first to tag this record!
_version_ 1823860569363447808
author Lior Gishboliner
Asaf Shapira
Yuval Wigderson
author_facet Lior Gishboliner
Asaf Shapira
Yuval Wigderson
author_sort Lior Gishboliner
collection DOAJ
description The triangle removal states that if G contains $\varepsilon n^2$ edge-disjoint triangles, then G contains $\delta (\varepsilon )n^3$ triangles. Unfortunately, there are no sensible bounds on the order of growth of $\delta (\varepsilon )$ , and at any rate, it is known that $\delta (\varepsilon )$ is not polynomial in $\varepsilon $ . Csaba recently obtained an asymmetric variant of the triangle removal, stating that if G contains $\varepsilon n^2$ edge-disjoint triangles, then G contains $2^{-\operatorname {\mathrm {poly}}(1/\varepsilon )}\cdot n^5$ copies of $C_5$ . To this end, he devised a new variant of Szemerédi’s regularity lemma. We obtain the following results: • We first give a regularity-free proof of Csaba’s theorem, which improves the number of copies of $C_5$ to the optimal number $\operatorname {\mathrm {poly}}(\varepsilon )\cdot n^5$ . • We say that H is $K_3$ -abundant if every graph containing $\varepsilon n^2$ edge-disjoint triangles has $\operatorname {\mathrm {poly}}(\varepsilon )\cdot n^{\lvert V(H)\rvert }$ copies of H. It is easy to see that a $K_3$ -abundant graph must be triangle-free and tripartite. Given our first result, it is natural to ask if all triangle-free tripartite graphs are $K_3$ -abundant. Our second result is that assuming a well-known conjecture of Ruzsa in additive number theory, the answer to this question is negative.
format Article
id doaj-art-5d4867e778644355bb56101ef6f97ac5
institution Kabale University
issn 2050-5094
language English
publishDate 2025-01-01
publisher Cambridge University Press
record_format Article
series Forum of Mathematics, Sigma
spelling doaj-art-5d4867e778644355bb56101ef6f97ac52025-02-10T12:03:33ZengCambridge University PressForum of Mathematics, Sigma2050-50942025-01-011310.1017/fms.2024.68An efficient asymmetric removal lemma and its limitationsLior Gishboliner0https://orcid.org/0000-0003-0688-8111Asaf Shapira1https://orcid.org/0000-0001-9902-0164Yuval Wigderson2https://orcid.org/0000-0001-5909-9250Department of Mathematics, University of Toronto, Toronto, Canada; E-mail:School of Mathematics, Tel Aviv University, Tel Aviv, IsraelInstitute for Theoretical Studies, ETH Zürich, Zürich, Switzerland; E-mail:The triangle removal states that if G contains $\varepsilon n^2$ edge-disjoint triangles, then G contains $\delta (\varepsilon )n^3$ triangles. Unfortunately, there are no sensible bounds on the order of growth of $\delta (\varepsilon )$ , and at any rate, it is known that $\delta (\varepsilon )$ is not polynomial in $\varepsilon $ . Csaba recently obtained an asymmetric variant of the triangle removal, stating that if G contains $\varepsilon n^2$ edge-disjoint triangles, then G contains $2^{-\operatorname {\mathrm {poly}}(1/\varepsilon )}\cdot n^5$ copies of $C_5$ . To this end, he devised a new variant of Szemerédi’s regularity lemma. We obtain the following results: • We first give a regularity-free proof of Csaba’s theorem, which improves the number of copies of $C_5$ to the optimal number $\operatorname {\mathrm {poly}}(\varepsilon )\cdot n^5$ . • We say that H is $K_3$ -abundant if every graph containing $\varepsilon n^2$ edge-disjoint triangles has $\operatorname {\mathrm {poly}}(\varepsilon )\cdot n^{\lvert V(H)\rvert }$ copies of H. It is easy to see that a $K_3$ -abundant graph must be triangle-free and tripartite. Given our first result, it is natural to ask if all triangle-free tripartite graphs are $K_3$ -abundant. Our second result is that assuming a well-known conjecture of Ruzsa in additive number theory, the answer to this question is negative. https://www.cambridge.org/core/product/identifier/S2050509424000689/type/journal_article05C3511B75
spellingShingle Lior Gishboliner
Asaf Shapira
Yuval Wigderson
An efficient asymmetric removal lemma and its limitations
Forum of Mathematics, Sigma
05C35
11B75
title An efficient asymmetric removal lemma and its limitations
title_full An efficient asymmetric removal lemma and its limitations
title_fullStr An efficient asymmetric removal lemma and its limitations
title_full_unstemmed An efficient asymmetric removal lemma and its limitations
title_short An efficient asymmetric removal lemma and its limitations
title_sort efficient asymmetric removal lemma and its limitations
topic 05C35
11B75
url https://www.cambridge.org/core/product/identifier/S2050509424000689/type/journal_article
work_keys_str_mv AT liorgishboliner anefficientasymmetricremovallemmaanditslimitations
AT asafshapira anefficientasymmetricremovallemmaanditslimitations
AT yuvalwigderson anefficientasymmetricremovallemmaanditslimitations
AT liorgishboliner efficientasymmetricremovallemmaanditslimitations
AT asafshapira efficientasymmetricremovallemmaanditslimitations
AT yuvalwigderson efficientasymmetricremovallemmaanditslimitations