N-(4-Methoxy-2-methyl-5-nitrophenyl)acetamide

In the title compound, C10H12N2O4, the four substituents lie out of the phenyl plane by varying degrees. The methyl C atom lies 0.019 (3) Å out of plane, while the methoxy O and C atoms lie 0.067 (2) and 0.042 (3) Å out of plane, respectively, with the C—C—O—C torsion angle being 3.3 (2)°. The plane...

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Bibliographic Details
Main Authors: Rao M. Uppu, Frank R. Fronczek
Format: Article
Language:English
Published: International Union of Crystallography 2025-06-01
Series:IUCrData
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Online Access:https://journals.iucr.org/paper?S2414314625004705
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Description
Summary:In the title compound, C10H12N2O4, the four substituents lie out of the phenyl plane by varying degrees. The methyl C atom lies 0.019 (3) Å out of plane, while the methoxy O and C atoms lie 0.067 (2) and 0.042 (3) Å out of plane, respectively, with the C—C—O—C torsion angle being 3.3 (2)°. The plane of the nitro group is twisted out of the phenyl plane, forming a dihedral angle of 12.03 (9)° with it. The acetamide substituent is twisted considerably more out of the phenyl plane, forming a dihedral angle of 47.24 (6)° with it. In the extended structure, the acetamide NH group donates a hydrogen bond to an acetamide carbonyl O atom, thereby forming chains propagating in the [010] direction.
ISSN:2414-3146