DP1 and completely continuous operators
W. Freedman introduced an alternate to the Dunford-Pettis property, called the DP1 property, in 1997. He showed that for 1≤p<∞, (⊕α∈𝒜Xα)p has the DP1 property if and only if each Xα does. This is not the case for (⊕α∈𝒜Xα)∞. In fact, we show that (⊕α∈𝒜Xα)∞ has the DP1 property if and only if it ha...
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Format: | Article |
Language: | English |
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Wiley
2003-01-01
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Series: | International Journal of Mathematics and Mathematical Sciences |
Online Access: | http://dx.doi.org/10.1155/S0161171203302315 |
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author | Elizabeth M. Bator Dawn R. Slavens |
author_facet | Elizabeth M. Bator Dawn R. Slavens |
author_sort | Elizabeth M. Bator |
collection | DOAJ |
description | W. Freedman introduced an alternate to the
Dunford-Pettis property, called the DP1 property,
in 1997. He showed that for 1≤p<∞,
(⊕α∈𝒜Xα)p has the DP1 property if and only if each Xα does. This is not the case for (⊕α∈𝒜Xα)∞. In
fact, we show that (⊕α∈𝒜Xα)∞ has the DP1 property if and only if it has
the Dunford-Pettis property. A similar result also
holds for vector-valued continuous function spaces. |
format | Article |
id | doaj-art-216ee22562d34931bcbc9906ccbc45f0 |
institution | Kabale University |
issn | 0161-1712 1687-0425 |
language | English |
publishDate | 2003-01-01 |
publisher | Wiley |
record_format | Article |
series | International Journal of Mathematics and Mathematical Sciences |
spelling | doaj-art-216ee22562d34931bcbc9906ccbc45f02025-02-03T05:57:57ZengWileyInternational Journal of Mathematics and Mathematical Sciences0161-17121687-04252003-01-012003372375237810.1155/S0161171203302315DP1 and completely continuous operatorsElizabeth M. Bator0Dawn R. Slavens1Department of Mathematics, University of North Texas, P.O. Box 311400, Denton 76203-1400, TX, USADepartment of Mathematics, Midwestern State University, 3410 Taft Blvd, Wichita Falls 76308, TX, USAW. Freedman introduced an alternate to the Dunford-Pettis property, called the DP1 property, in 1997. He showed that for 1≤p<∞, (⊕α∈𝒜Xα)p has the DP1 property if and only if each Xα does. This is not the case for (⊕α∈𝒜Xα)∞. In fact, we show that (⊕α∈𝒜Xα)∞ has the DP1 property if and only if it has the Dunford-Pettis property. A similar result also holds for vector-valued continuous function spaces.http://dx.doi.org/10.1155/S0161171203302315 |
spellingShingle | Elizabeth M. Bator Dawn R. Slavens DP1 and completely continuous operators International Journal of Mathematics and Mathematical Sciences |
title | DP1 and completely continuous operators |
title_full | DP1 and completely continuous operators |
title_fullStr | DP1 and completely continuous operators |
title_full_unstemmed | DP1 and completely continuous operators |
title_short | DP1 and completely continuous operators |
title_sort | dp1 and completely continuous operators |
url | http://dx.doi.org/10.1155/S0161171203302315 |
work_keys_str_mv | AT elizabethmbator dp1andcompletelycontinuousoperators AT dawnrslavens dp1andcompletelycontinuousoperators |