DP1 and completely continuous operators
W. Freedman introduced an alternate to the Dunford-Pettis property, called the DP1 property, in 1997. He showed that for 1≤p<∞, (⊕α∈𝒜Xα)p has the DP1 property if and only if each Xα does. This is not the case for (⊕α∈𝒜Xα)∞. In fact, we show that (⊕α∈𝒜Xα)∞ has the DP1 property if and only if it ha...
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Main Authors: | , |
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Format: | Article |
Language: | English |
Published: |
Wiley
2003-01-01
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Series: | International Journal of Mathematics and Mathematical Sciences |
Online Access: | http://dx.doi.org/10.1155/S0161171203302315 |
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Summary: | W. Freedman introduced an alternate to the
Dunford-Pettis property, called the DP1 property,
in 1997. He showed that for 1≤p<∞,
(⊕α∈𝒜Xα)p has the DP1 property if and only if each Xα does. This is not the case for (⊕α∈𝒜Xα)∞. In
fact, we show that (⊕α∈𝒜Xα)∞ has the DP1 property if and only if it has
the Dunford-Pettis property. A similar result also
holds for vector-valued continuous function spaces. |
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ISSN: | 0161-1712 1687-0425 |