A new inequality for a polynomial
Let p(z)=a0+∑j=tnajzj be a polynomial of degree n, having no zeros in |z|<k, k≥1 then it has been shown that for R>1 and |z|=1, |p(Rz)−p(z)|≤(Rn−1)(1+AtBtKt+1)/(1+kt+1+AtBt(kt+1+k2t))max|z|=1|p(z)|−{1−(1+AtBtkt+1)/(1+kt+1+AtBt(kt+1+k2t))}((Rn−1)m/kn), where m=min|z|=k|p(z)|, 1≤t<n, At=(Rt−1...
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| Main Authors: | , , |
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| Format: | Article |
| Language: | English |
| Published: |
Wiley
2001-01-01
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| Series: | International Journal of Mathematics and Mathematical Sciences |
| Online Access: | http://dx.doi.org/10.1155/S0161171201006032 |
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